find the area of sector of a circle with radius 6 cm if angle of the sector is 60° ?
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Answered by
3
area of sector = (pie r.r./2pie )× pie/3
= r.r pie/6
= 36pie/6 = 6 pie = 18.84
= r.r pie/6
= 36pie/6 = 6 pie = 18.84
Answered by
21
we know that area A of a sector of angle theta in .
a circle of radius r is given by A = theta / 360 × πr^2
here
r = 6 cm , theta =60°
A= [ 60 / 360 × 22/ 7 × 36] cm^2
(132/7 ) cm^2
be brainly
a circle of radius r is given by A = theta / 360 × πr^2
here
r = 6 cm , theta =60°
A= [ 60 / 360 × 22/ 7 × 36] cm^2
(132/7 ) cm^2
be brainly
ddd2768:
Right answer
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