find the area of sector of a criclevof radius 18cm with central angle 35
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Area of sector = pi *r^2 * A / 360
= 22*18*18*35/ 7 *360
= 22*18*5/20
= 22*18/4
= 11*9
= 99 cm^2
= 22*18*18*35/ 7 *360
= 22*18*5/20
= 22*18/4
= 11*9
= 99 cm^2
Answered by
3
Given
Radius is 18
Theta is 35
Hence area of sector is
Theta/360 pi r^2
35/360x22/7x18x18
132 cm sq
Radius is 18
Theta is 35
Hence area of sector is
Theta/360 pi r^2
35/360x22/7x18x18
132 cm sq
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