Question

Find the area of sector of circle of radius 3.5 and angle of the sector is 90'​

Answer 1

Answer:

Given :-

• A circle whose radius is 3.5 cm and the angle of the sector is 90°.

To Find :-

• What is the area of sector of circle.

Formula Used :-

$\clubsuit$ Area Of Sector Of Circle Formula :

$\mapsto \sf\boxed{\bold{\pink{Area\: Of\: Sector =\: \dfrac{\theta}{360^{\circ}} \times {\pi}r^2}}}$

where,

• $\sf \theta$ = Central Angle
• r = Radius
• π = pie or 22/7

Solution :-

Given :

• Central Angle $\bf (\theta)$ = 90°
• Radius (r) = 3.5 cm

According to the question by using the formula we get,

$\longrightarrow \sf Area\: Of\: Sector =\: \dfrac{90^{\circ}}{360^{\circ}} \times \dfrac{22}{7} \times (3.5)^2$

$\longrightarrow \sf Area\: Of\: Sector =\: \dfrac{\cancel{90^{\circ}}}{\cancel{360^{\circ}}} \times \dfrac{22}{7} \times 3.5 \times 3.5$

$\longrightarrow \sf Area\: Of\: Sector =\: \dfrac{1}{4} \times \dfrac{22}{7} \times 12.25$

$\longrightarrow \sf Area\: Of\: Sector =\: \dfrac{22}{28} \times 12.25$

$\longrightarrow \sf Area\: Of\: Sector =\: \dfrac{269.5}{28}$

$\longrightarrow \sf\bold{\red{Area\: Of\: Sector =\: 9.625\: cm^2}}$

${\small{\bold{\underline{\therefore\: The\: area\: of\: sector\: of\: circle\: is\: 9.625\: cm^2\: .}}}}$