Math, asked by kalpeshwarneha, 5 months ago

Find the area of sector of circle with radius 4cm and of angle 30° also find the area of the corresponding major sector (use π=3.14)​

Answers

Answered by Sameeksha7
4

ANSWER

We have,

Let the radius of circle r=4cm.

Angle θ=30

Area of sector of circle =

0 / 360 ×πr ^2

4 / 3 ×3.14

=4.186cm ^ 2

Area of major sector = Area of circle-area of minor sector

=πr

2

−4.186

=3.14×4×4−4.186

=3.14×16−4.186

=50.24cm.

2

Hence, this is the answer.

Answered by Anonymous
37

Given:

  • Radius = 4 cm
  • Angle = 30°

To Find:

  • Area of sector of a circle
  • Area of corresponding major sector

Solution:

Given sector is OAPB.

As we know:

★Area of sector = θ/360 × πr²

→ 30/360 × 3.14 × 4 × 4 cm²

→ 12.56/3 cm²

→ 4.19cm² (approx.)

Area of corresponding major sector:-

→ πr² - area of sector OAPB

→ (3.14 × 16 - 4.19) cm²

→ 46.05 cm²

→ 46.1 cm² (approx.)

Alternatively,

★Area of major sector = (360 - θ)/360 × πr²

→ (360 - 30/360) × 3.14 × 16 cm²

→ 330/360 × 3.14 × 16cm2

→ 46.1 cm² (approx.)

Hence,

  • Area of sector = 4.19 cm²
  • Area of major sector = 46.1 cm²
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