Find the area of sector of circle with radius 4cm and of angle 30° also find the area of the corresponding major sector (use π=3.14)
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Answered by
4
ANSWER
We have,
Let the radius of circle r=4cm.
Angle θ=30
Area of sector of circle =
0 / 360 ×πr ^2
4 / 3 ×3.14
=4.186cm ^ 2
Area of major sector = Area of circle-area of minor sector
=πr
2
−4.186
=3.14×4×4−4.186
=3.14×16−4.186
=50.24cm.
2
Hence, this is the answer.
Answered by
37
Given:
- Radius = 4 cm
- Angle = 30°
To Find:
- Area of sector of a circle
- Area of corresponding major sector
Solution:
Given sector is OAPB.
As we know:
★Area of sector = θ/360 × πr²
→ 30/360 × 3.14 × 4 × 4 cm²
→ 12.56/3 cm²
→ 4.19cm² (approx.)
★Area of corresponding major sector:-
→ πr² - area of sector OAPB
→ (3.14 × 16 - 4.19) cm²
→ 46.05 cm²
→ 46.1 cm² (approx.)
Alternatively,
★Area of major sector = (360 - θ)/360 × πr²
→ (360 - 30/360) × 3.14 × 16 cm²
→ 330/360 × 3.14 × 16cm2
→ 46.1 cm² (approx.)
Hence,
- Area of sector = 4.19 cm²
- Area of major sector = 46.1 cm²
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Anonymous:
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