Question

Find the area of sector whose central angle is 60° and r = 42 ​

Answer 1

Given that radius r=42 cm and θ=60
∘
.
Therefore,
length of arc l=
360
∘

θ
​
×2πrl=
360
∘

θ
​
×2πr
=
360
∘

60
∘

​
×2×
7
22
​
×42=44cm.=
360
∘

60
∘

​
×2×
7
22
​
×42=44cm.
Area of the sector =
2
lr
​
=
2
44×42
​
=924cm
2

Perimeter=l+2r=44+2(42)=128cm

Answer 2

Hello, Buddy!!

Given:-

• Centre Angle of the circle is 60°
• Radius (r) is 42units.

To Find:-

• Area of Sector.

Required Solution:-

$\frac{ 60 }{360} \times \frac{22}{7} \times 42 \times 42 \\ \frac{1}{6} \times 22 \times 6 \times 42 \\ 22 \times 42 \\ 924$

• Area of Sector ➪ 924sq.units

Formulas Used:-

• $\sf{Area\;of\; Sector = \bold{\frac{\theta}{360}{\pi}r^{2}}}$

@MrMonarque♡

Hope It Helps You ✌️