find the area of sector whose
length of the arc is 12.5 cm and radius is 6 CM
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Answer:
perimeter of the sector=12.5+2(6)=24.5
let angle subtend by the arc be =@
Step-by-step explanation:
=@/360×2πr=24.5
=@/360×37.68=24.5
=@/360=24.5/37.68
=@/360=0.65
area of the sector=@/360×πr^2
so,πr^2=113.04
=@/360×πr^2=0.65×113.04
=73.476
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