Question

Find the area of semicircle whose perimeter 54cm and 144 cm

Answer 1

Answer:

The perimeter of semicircle is 144 cm, which is equal to 2r + (pi)r, where r= radius.

2r + (pi)r = r(14+22)/7 = r(36/7) so r = 144*7/36 = 28 cm.

The area of the semicircle is = (22/7)*28^2/2 = 1232 sq cm.

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Answer 2

Perimeter of semi circle = πr

According to question

πr = 54

r = 54/π

area = πr^2 = π*54*7/22*π= 388/22= 194/11cm^2

again

r = 144/π

area = π*144*7/22*π= 72*7/11= 504/11