Find the area of semicircle whose perimeter 54cm and 144 cm
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Answered by
5
Answer:
The perimeter of semicircle is 144 cm, which is equal to 2r + (pi)r, where r= radius.
2r + (pi)r = r(14+22)/7 = r(36/7) so r = 144*7/36 = 28 cm.
The area of the semicircle is = (22/7)*28^2/2 = 1232 sq cm.
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Answered by
4
Perimeter of semi circle = πr
According to question
πr = 54
r = 54/π
area = πr^2 = π*54*7/22*π= 388/22= 194/11cm^2
again
r = 144/π
area = π*144*7/22*π= 72*7/11= 504/11
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