Question

find the area of shaded part.​

Answer 1

Step-by-step explanation:

216

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Answer 2

Solution

$xy = \sqrt{12 {}^{2} + 12 {}^{2} } = \sqrt{288} = 12 \sqrt{2}$

$xb = yb = \sqrt{24 {}^{2} + 12 {}^{2} } = 12 \sqrt{5}$

now ......

area of the ....∆XYB (isosceles triangle)..is

$= \frac{1}{4} \times 12 \sqrt{2} \times \sqrt{4 \times (12 \sqrt{5}) {}^{2} - (12 \sqrt{2} ) {}^{2} } \\ = 3 \sqrt{2} \times \sqrt{144 \times 18} \\ = 216 \: \: cm {}^{2}$