Question

Find the area of shaded portion

Answer 1

Answer:

area of rectangle =200m

area of 1st triangle= 56m

area of 2nd triangle = 12 m

area of 3rd triangle = 48m

area of 4th triangle = 4m

area of shaded portion = 200-56-48-12-4

= 200-120

= 60m

Answer 2

Answer:

Step-by-step explanation:

Its a rectangle

So area of whole rectangle = 10×20=200$m^{2}$(1)

Now

Area of Δ AFE=$\frac{1}{2}$×base×height

=$\frac{1}{2}$×14×8

=56$m^{2}$

Similarly

Area of Triangle EDH,HGC,FBG are 12$m^{2}$,48$m^{2}$ and 4$m^{2}$ respectively

Therefore area of unshaded region= 56+12+48+4

=120$m^{2}$

From (1)

Area of Shaded region=Area of Unshaded regions(Triangles)-Area of rectangle

=200-120

=80$m^{2}$

(or) 8000$cm^{2}$

I hope This helps you

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