Question

find the area of shaded portion in figure 1 and 2​

Answer 1

Answer:

110cm^2

Step-by-step explanation:

fig 1

$\frac{1}{2} * 8*10+\frac{1}{2} *10*6+4*10\\\\40+30+40 \\110cm^{2}$

Answer 2

Step-by-step explanation:

Figure A

area of rect. ABCD=18×10=180cm2

Area of tri. AFE=1/2×6×10=30cm2

Area of tri. BCE=1/2×10×8=40cm2

Area of shaded portion=180-40-30

=110cm2

Figure2

Area of squarePQRS= 20×20=400cm2

Area of tri.TSU= 1/2×10×10=50cm2

Area of tri.PTQ=1/2×10×20=100cm2

Area of tri.QRU=1/2×10×20=100cm2

Area of shaded portion= 400-100-100-50

=150cm2

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