find the area of shaded region (herons formula)
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Step-by-step explanation:
perimeter of triangle ABC
= 120 + 122 + 22 = 264m
semi perimeter
s = 264/2 = 132 m
area of triangle ABC
= √[(132(132-122)(132-120)(132-22)]
= 1320m^2
perimeter of inner triangle BOC
= 24+26+22 = 72 m
s = 72/2 = 36m
area of Triangle BOC
= √[36(36-24)(36-26)(36-22)]
= 245.92 => 246m^2 (approx)
area of shaded region
= 1320 - 246 = 1074m^2 Ans
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