Question

find the area of shaded region in given figure where arcs drawn with centre A B C D intersects in pair at midpoint p c R and S of the sides AB, BC, CD, DA are respectively of a square ABCD of sides 12 cm ​

Answer 1

Area of quadrant = \bf\huge\frac{1}{4} \pi r^{2}41​πr2


Area of quadrant = \bf\huge\frac{1}{4} \times3.14\times6^{2}41​×3.14×62


Area of 4 quadrant = \bf\huge 4\times\frac{1}{4} \times3.14\times364×41​×3.14×36


= 3·14 × 36


= 113·04 cm^2


Area of shaded region = Area of square  – Area of 4 Quadrant


= 144 – 113·04


Area of shaded region = 30·96 cm^2
Plz follow

Answer 2

Area of the shaded region = Area of the square ABCD - 4 × Area of a quadrant or a circle with r = 6cm

$\longrightarrow$$\sf{12cm \times 12cm - \times \frac{1}{4} = 3.14 \times 6cm \times 6cm}$

$\longrightarrow$$\sf{(144 - 113.04) {cm}^{2} }$

$\longrightarrow$${\boxed{\sf{\red{{30.96cm}^{2}}}}}$