find the area of shaded region where a circle and of radius 6cm has been drawn with vertex o of an equilateral triangle OAB of side 12cm and should in point
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Area of circle =πr²=3.14*6*6=
113.04cm²
Area of equilateral triangle =
A=√3/4a²=√3/4*12*12
1.73*36=62.28cm²
In an equilateral triangle each vertex angle is 60°
Area of sector OLP=θ/360*πr²
60/360*3.14*6*6
1/6*113.04=18.84cm²
Now,
Area of shaded portion=Area of circle + Area of equilateral triangle - Area of sector
113.04+62.28-18.84
175.32-18.84=156.48cm²
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hope it helps you ok
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dineshmeenarock:
Thanks ✌️
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