find the area of shaded region where a circle of radius 6cm has been drawn with vertex of an equilateral triangle OAB of side 12cm. (π = 3.14 and √3=1.73)
Answers
Area of the sector is common in both.
Radius of the circle = 6 cm.
Side of the triangle = 12 cm.
Area of the equilateral triangle = √3/4 × (OA)2 = √3/4 × 122 = 36√3 cm2
Area of the circle = π R2 = 22/7 × 62 = 792/7 cm2
Area of the sector making angle 60° = (60°/360°) × π r2 cm2
= 1/6 × 22/7 × 62 cm2 = 132/7 cm2
Area of the shaded region = Area of the equilateral triangle + Area of the circle - Area of the sector
= 36√3 cm2 + 792/7 cm2 - 132/7 cm2
= (36√3 + 660/7) cm2
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Answer:
OAB is an equilateral triangle with each angle equal to 60°.
Area of the sector is common in both.
Radius of the circle = 6 cm.
Side of the triangle = 12 cm.
Area of the equilateral triangle = √3/4 × (OA)2 = √3/4 × 122 = 36√3 cm2
Area of the circle = π R2 = 22/7 × 62 = 792/7 cm2
Area of the sector making angle 60° = (60°/360°) × π r2 cm2
= 1/6 × 22/7 × 62 cm2 = 132/7 cm2
Area of the shaded region = Area of the equilateral triangle + Area of the circle - Area of the sector
= 36√3 cm2 + 792/7 cm2 - 132/7 cm2
= (36√3 + 660/7) cm2
hope this will help u plz follow me and Mark it as brainliest plz
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