find the area of shaded region where AGB,AEC,CFD,DGB are semicircles on diameter AB,AC,CD,DB respectively and AC:CD:DB= 3:2:2
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Answer:
Step-by-step explanation:
Area (APD) = pi/2 * 7^2
= 77
Area (AQB) = pi/2 * 1.75^2
= 4.81
Area ( BRC) = pi/2 * 49/4
= 77/4 = 19.25
Area (CSD) = pi/2 * 1.75^2
= 4.81
Thus Area of shaded Region = 77+ 2* 4.81 + 19.25
= 105.87 unit sqr
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