Find the area of shaded region where arcs APD AQB BRC and CSD are semicircles of diameter 14 ,3.5,7,3.5 respectively
Answers
Answered by
67
Area (APD) = pi/2 * 7^2
= 77
Area (AQB) = pi/2 * 1.75^2
= 4.81
Area ( BRC) = pi/2 * 49/4
= 77/4 = 19.25
Area (CSD) = pi/2 * 1.75^2
= 4.81
Thus Area of shaded Region = 77+ 2* 4.81 + 19.25
= 105.87 unit sqr
= 77
Area (AQB) = pi/2 * 1.75^2
= 4.81
Area ( BRC) = pi/2 * 49/4
= 77/4 = 19.25
Area (CSD) = pi/2 * 1.75^2
= 4.81
Thus Area of shaded Region = 77+ 2* 4.81 + 19.25
= 105.87 unit sqr
shabeebkv17p3t8vp:
brother,u should subtract 2*4.81
Answered by
1
77cm^2 is the area of the shaded region.
Step-by-step explanation:
Given that daimeters of semicircles:
ar(APD) = 14cm
ar(BRC) = 3.5 cm
ar(AQB) = 7 cm
ar(CD) = 3.5 cm
To find the area of shaded region;
⇒ ar(APD) + ar(BRC) − ar(AQB) − ar(CD)
⇒ {(3.5 + 3.5)^2/2 + (3.5)^2/2 - (3.5)^2/2} * 2
= 77 cm^2
∵ The area of the shaded region = 77cm^2
Learn more: find the area
brainly.in/question/3996219
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