Find the area of smaller part of the ellipse
y?
y
= 1 and the line +
= 1.
4 9
2 3
+२
x
+
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Answer:
The area of the smaller region by the ellipse 9x2+4y2=1 and the line 3x+2y=1represented by the shaded region BCAB
∴Area BCAB=Area (OBCAO)−Area (OBAO)
=∫0321−9x2dx−∫032(1−3x)dx
=32[∫039−x2dx]−32∫03(3−x)dx
=32[2x9−x2+29sin
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