find the area of spcial quadrilateral whose diagnol lenght is 6 cm. And the length of two perpendicular on given diagonal from the vertices are 3cm and 4cm
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Answer:
In quad. ABCD
AC = 12 cm
DL = 8 cm
BM = 7 cm
Now in triangle ADC
Base = AC = 12
Height = DL = 8
Area = 1/2 ×b ×h
=> 1/2 × 12 × 8
=> 48 Sq cm
Again in triangle ABC
Base = AC = 12
Height = BM = 7
Area = 1/2 × b × h
=> 1/2 × 12 × 7
=> 42 Sq cm
Now total area of quad ABCD = Area of triangle ADC + Area of triangle ABC
=>( 48 + 42 ) Sq cm
=> 90 Sq cm
Hope it helps uh...
Thanks...☺☺✌
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