Find the area of square ABCD where coordinates of A,B,C,D are [0,0],[1,2],[2,5] and [1,4] respectively.
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Answered by
9
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Area of quadrilateral ABCD = Area of traingle ABC + Area of triangle ACD
Area of triangle
=
2
1
[x
1
(y
2
−
y
3
3
x
2
y
1
1
x
3
y
2
Area of triangle ABC
=
2
1
[1(−3−
2)+
7(2−
1)+
12(1+
3)]
=
24
square units
Area of triangle ACD
=
2
1
[1(2−
21)+
12(21−
1)+
7(1−
2)]
=
107
square units
Therefore, area of quadrilateral ABCD
=
25+
107=
132
sq. units
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Answered by
5
Area of quadrilateral ABCD = Area of traingle ABC + Area of triangle ACD
refer to the attachment
Pls follow
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