Find the area of square of length 4 cm. Find the area of a rectangle having 0 length 8 cm and breadth 2 cm. What is the difference of two areas ?
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0
Answer:
Answer
Let side of square be 5cm
Area of rectangle =32×8
Area of square=s
2
s
2
=32×8
s
2
=2
8
s=2
4
=16cm
Difference of the perimeters =2(32+8)−4×16
=80−64
=16cm
Step-by-step explanation:
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4
Answer :
Area of square = 4 × 4 = 16cm^2
Area of rectangle = l × b = 8 × 2 = 16cm^2
Difference between the areas of square and rectangle = 16 - 16 = 0
Hence , there is no difference between the two areas.
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