Question

Find the area of square of length 4 cm. Find the area of a rectangle having 0 length 8 cm and breadth 2 cm. What is the difference of two areas ?​

Answer 1

Answer:

Answer

Let side of square be 5cm

Area of rectangle =32×8

Area of square=s

2

s

2

=32×8

s

2

=2

8

s=2

4

=16cm

Difference of the perimeters =2(32+8)−4×16

=80−64

=16cm

Step-by-step explanation:

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Answer 2

Answer :

Area of square = 4 × 4 = 16cm^2

Area of rectangle = l × b = 8 × 2 = 16cm^2

Difference between the areas of square and rectangle = 16 - 16 = 0

Hence , there is no difference between the two areas.

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