Question

Find the area of square of length 4cm. Find the area of a rectangle having length 8cm breadth 2cm. What is the difference of two areas

Answer 1

Step-by-step explanation:

$area \: of \: square = length \times length \\ \\ \: \: \: = 4 \times 4 = 16 {cm}^{2} \\ \\ area \: of \: rectangle = length \: \times breadth \\ \\ \\ \: \: \: \: = 8 \times 2 = 16 {cm}^{2} \\ \\ \\ difference \: between \: two \: area \: is \: 0$

Answer 2

~Anzwer :-

Here, we have been given;

Side of Square = 4 cm

Length of Rectangle = 8 cm

Breadth of Rectangle = 2 cm

Now,

• Area of Square :-

We know that,

$ \rm{Area~ of~ Square~ : ~Side \times Side}$

$\rm{= 4 \: cm\times 4 \: cm}$

$\rm{ = 16 \: {cm}^{2} }$

Next,

• Area of Rectangle :-

We know that,

$ \rm{Area~ of ~Rectangle~ : ~Length \times Breadth}$

$\rm{ = 8 \: cm \times 2 \: cm}$

$\rm{ = 16 \: {cm}^{2} }$

★ Difference :-

Now,

• Area of Rectangle = 16 cm²
• Area of Square = 16 cm²

Hence,

16 cm² - 16 cm²

= 0 cm²

∴ Hence, the difference between the areas of rectangle and the square will be of 0 cm².

• This can be said is the areas of both the figures have no difference.