find the area of square park whose perimeter is 48m.
deshmukhanish:
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![perimeter\: of \: square \: park = \\ 4 \times side \\ 4 \times side = 48 \\ side= \frac{48}{4} \\ side = 12 perimeter\: of \: square \: park = \\ 4 \times side \\ 4 \times side = 48 \\ side= \frac{48}{4} \\ side = 12](https://tex.z-dn.net/?f=+perimeter%5C%3A+of+%5C%3A+square+%5C%3A+park+%3D+%5C%5C+4+%5Ctimes+side+%5C%5C+4+%5Ctimes+side+%3D+48+%5C%5C+side%3D+%5Cfrac%7B48%7D%7B4%7D+%5C%5C+side+%3D+12+)
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SO, THE SIDE OF THE SQUARE = 12 m
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![area \: of \: square \: = {side}^{2} \\ = {12}^{2} \\ = 144 \: {m}^{2} area \: of \: square \: = {side}^{2} \\ = {12}^{2} \\ = 144 \: {m}^{2}](https://tex.z-dn.net/?f=area+%5C%3A+of+%5C%3A+square+%5C%3A+%3D+%7Bside%7D%5E%7B2%7D+%5C%5C+%3D+%7B12%7D%5E%7B2%7D+%5C%5C+%3D+144+%5C%3A+%7Bm%7D%5E%7B2%7D+)
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SO, THE SIDE OF THE SQUARE = 12 m
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Answered by
0
perimeter of a square=4×side
48=4 ×side
side= 12m
area =12×12
= 144m^2
48=4 ×side
side= 12m
area =12×12
= 144m^2
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