find the area of square pqrs whose perimeter is 40m and diagonal is 16m
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Answered by
0
Answer:
perimeter of square=40m
digonal of square=16m
let AB=BC=X
in ∆ABC angle ABC=90°
by Pythagoras theorem
AB^2=BC^2+AB^2
16^2=x^2+x^2
256=2x^2
256/2=x^2
128=x^2
x=√128
x=8√2
side of square is 8√2
area of square=side^2
=[8√2]^2
=128 sq m
Answered by
1
Answer:
diagonal=√2a
16=√2a
16/√2=a
a=16/√2
a=16×√2/√2×√2
a=16√2/2
a=8√2m
area of square=a²
=8√2×8√2
=64×2
=128m²
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