find the area of square that has the same perimeter as a rectangle whose length and breadth are 18cm and 8cm respectively
Answers
Answer:
Step-by-step explanation:
perimeter of rectangle=2x(l+b)
=2(18+8)
=52
ATQ-perimeter of rectangle=perimeter of square
so, 52= 4xside
so,52/4=side of square
13=side of square
now we can find area of square i.e. sidexside
=13x13=169
so,169 is the area of that square
Answer :
169 cm²
Solution :
Here ,
The given length and breadth of rectangle are 18 cm and 8 cm respectively .
Now ,
The perimeter of the rectangle will be given as ;
=> P = 2(L + B)
=> P = 2(18 + 8)
=> P = 2×26
=> P = 52
According to the question , a square has the same perimeter as the rectangle .
=> P = 52
=> 4•Side = 52
=> Side = 52/4
=> Side = 13
Now ,
The area of the square will be ;
=> A = Side²
=> A = 13²
=> A = 169