Question

find the area of square the length of its diagonals is 8√2​

Answer 1

Answer:

given that ,

diagonal of a square ( d )= 8√2

we know that, d² = a² + a² = 2a²

=> a² = d²/2

so area of a square (a²) = (8√2)²/2

= (64 × 2)/2

= 64

hope it helps you!!