Question

find the area of square the length of whose diagonal is 64 cm

Answer 1

$let \: the \: side \: of \: square \: be \: a \\ then \\ {a}^{2} + {a}^{2} = 64 \\ 2 {a}^{2} = 64 \\ {a }^{2} = 32 \\ so \: the \: area \: ofsquare = 32 {cm}^{2}$

Answer 2

Answer:

Step-by-step explanation:-

Area of any quadrilateral=

(1/2)(diagnol1)(diagnol2)

=(1/2)(64*64)

=1/2*4096

=2048cm^2