Question

Find the area of square where diagonal is 58V2 cm.(please send my question)​

Answer 1

Answer:

Given, the length of the diagonal is 58√2.

Let the sides of the square be 'x'.

As all angles are right angles in a square, by Pythagoras theorem,

x² + x² = (58√2)²

=> 2(x²) = 6728

=> x² = 3364 cm²

x² is the area of the square as it the product of two sides of the square...

Therefore, the area is 3364 cm²