find the area of square whose daigonal is of 14cm
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aloha!
>>--------☺️-------<<
we know that area of square is side × side
but what we are given is just diagonal.
we can find the sides of the square by applying the Pythagoras theorem.
which is:
H^2 = P^2 + B^2
( H × H = P × P + B × B )
14^2 = P^2 + P^2.( since the sides of square are equal )
14 × 14 = 2P^2
196/2 = P^2
98 = P^2
P = √98
P = 7√2 cm = sides of square.
now, area of square = side × side
= 7√2 × 7√2
=49 × 2
= 98
>>--------☺️--------<<
hope it helps :)
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