Find the area of square whose diagonal is 6cm?
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as we know that diagonal of a square bisects
therefore , BO = OC = 3cm
now in triangle OBC = BO = 3cm
OC = 3cm
BC^2 = OC^2 + BO^2
= 3^2 + 3^2 cm^2
= 9 + 9 cm^2
= 18cm^2
therefore , BO = OC = 3cm
now in triangle OBC = BO = 3cm
OC = 3cm
BC^2 = OC^2 + BO^2
= 3^2 + 3^2 cm^2
= 9 + 9 cm^2
= 18cm^2
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BO = OC = 3cm
now in triangle OBC = BO = 3cm
OC = 3cm
BC^2 = OC^2 + BO^2
= 3^2 + 3^2 cm^2
= 9 + 9 cm^2
= 18cm^2
now in triangle OBC = BO = 3cm
OC = 3cm
BC^2 = OC^2 + BO^2
= 3^2 + 3^2 cm^2
= 9 + 9 cm^2
= 18cm^2
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