Question

Find the area of square whose (L) of its diagonal is 5cm.

Answer 1

let the side be x 

now, by pythagoras theorem,

x^2 + x^2 = 5^2

2x^2 = 25

x^2 =25/2

x^2 = 12.5cm


now,


area of square = side^2 = x^2 = 12.5cm^2


i hope this will help you


-by ABHAY

Answer 2

Hello Gunjan :))

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How is everything going up dude :??....

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well here is the answer ..

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length of the diagonbal is=5cm.

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therefore.. ACCORDING TO PYTHAGORAS THEOREM..............

..................................................SEE NICELY.............................................................
DIAGONAL SQUARE= SIDE1 SQUARE + SIDE 2 SQUARE.
Let the side of square= 'x'.

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therefore .

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x²+x²=5²
2x²=25
x=25/2
thereofre..

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x=5/√2..

therefore area of square=side²

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x=side=5/√2

therefore.

(5/√2)²=25/4-----------------------> cm²..................

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thereofree area = 25/4 cm²..

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hope it helps you...