find the area of square whose perimeter is 64 cm
Answers
Question :
To Find :
Given :
Required Formula :
Solution :
Therefore,The area of square is 256.
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More to know :
Area of rectangle = length × width
Area of triangle =
Area of trapezium =
Area of circle =
Area of parallelogram = breadth × height
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Answer:
\bigstar★ Question :
\longmapsto\bf{Find\:the\: area\: of\: square \:whose \:perimeter\: is \:64cm.}⟼Findtheareaofsquarewhoseperimeteris64cm.
\bigstar★ To Find :
\longmapsto⟼ \mathtt{Area \:of\: square = \:?}Areaofsquare=?
\bigstar★ Given :
\longmapsto⟼ \mathtt{Perimeter\: of\: square = 64 cm}Perimeterofsquare=64cm
\bigstar★ Required Formula :
\longmapsto⟼ \mathtt{Area\: of\: square = a^{2}}Areaofsquare=a
2
\longmapsto⟼ \mathtt{Perimeter\: of\: square = 4a}Perimeterofsquare=4a
\bigstar★ Solution :
\longmapsto⟼ \mathtt{64 = 4a}64=4a
\longmapsto⟼ \mathtt{a = \frac{64}{4}}a=
4
64
\longmapsto⟼ \mathtt{a = 16}a=16
\longmapsto⟼ \mathtt{Area\: of \:square = 16^2}Areaofsquare=16
2
\longmapsto⟼ \mathtt{Area\:of\:square = 16 \times 16}Areaofsquare=16×16
\longmapsto⟼ \mathtt{Area\:of\:square = 256 cm^2}Areaofsquare=256cm
2
Therefore,The area of square is 256\bf{cm^2}cm
2
.
________________________________________
More to know :
\longmapsto⟼ Area of rectangle = length × width
\longmapsto⟼ Area of triangle = \frac{l\times b}{2}
2
l×b
\longmapsto⟼ Area of trapezium = \frac{a+b}{2} h
2
a+b
h
\longmapsto⟼ Area of circle = {\pi r^2}πr
2
\longmapsto⟼ Area of parallelogram = breadth × height
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Step-by-step explanation:
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