Question

Find the area of square whose side is 2x+3 cm

Answer 1

Answer:

4x^2+12x+9

Step-by-step explanation:

To find the area of a square: s^2 (s=side length)

a=(2x+3)^2

a=(2x+3)(2x+3)

a=4x^2+6x+6x+9

a=4x^2+12x+9

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Answer 2

Given:

• The length of one side of the square = 2x+3 cm

To Find:

• The area of the square

Solution:

We know that,

Area of a square = (side × side) square.units → (equation 1)

On substituting the value of length of the side in equation 1 we get,

⇒ Area of a square = (2x+3)×(2x+3)

⇒ Area of a square = 4$x^2$+6x+6x+9

⇒ Area of square = (4$x^2$ + 12x + 9) square.units

∴ The area of a square = (4$x^2$ + 12x + 9) sq.units.