Find the area of square whose side is (5x-9z) units.
Answers
Answered by
0
Answer:
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I hope it helped.
Answered by
0
Answer:
25x^2 - 90xz + 81z^2
Step-by-step explanation:
Given
Side of square = 5x - 9z
area of square = a^2
area = (5x - 9z)^2
we know that
( a - b)^2 = a^2 - 2ab + b^2
a = 5x. b = 9z
area = (5x)^2 - 2(5x)(9z) + (9z)^2
area = 25x^2 - 90xz + 81z^2
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