Math, asked by khyatichawla08, 5 months ago

Find the area of square whose side is (5x-9z) units.

Answers

Answered by dipeshGR8
0

Answer:

God knows!!!!!!!

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.byee friends

I hope it helped.

Answered by srinija0419
0

Answer:

25x^2 - 90xz + 81z^2

Step-by-step explanation:

Given

Side of square = 5x - 9z

area of square = a^2

area = (5x - 9z)^2

we know that

( a - b)^2 = a^2 - 2ab + b^2

a = 5x. b = 9z

area = (5x)^2 - 2(5x)(9z) + (9z)^2

area = 25x^2 - 90xz + 81z^2

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