Question

find the area of square whose side is ( r - 2s)²

r² - 4 rs +2s²

r² - 4rs + 4s²

2r² - 4rs + 4s²​

Answer 1

We know:

$\bigstar \boxed{ \rm{}area = {side}^{2} }$

$\bf \to \: area = (r - 2s)^{2}$

$\bf \to \: area = { \bigg( {r}^{2} + {2s}^{2} - 2 \times 2s \times r\bigg) }^{2}$

$\bf \to \: area = { \bigg( {r}^{2} + {4s}^{2} -4sr \bigg) }$