Question

Find the area of square whose side length is 2m+3n+4l

Answer 1

Answer:

4m²+9n²+16l²+12mn+24nl+16ml

Step-by-step explanation:

area of square =side ×side

side=2m+3n+4l

area=(2m+3n+4l)²

=(2m)²+(3n)²+(4l)²+2(2m)(3n)+2(3n)(4l)+2(2m)(4l)

=4m²+9n²+16l²+12mn+24nl+16ml

Answer 2

Required answer:

$\red{area \: of \: square = { {9m}^{2} + {4n}^{2} + {16l}^{2} + 12mn - 16ln - 24lm} \: sq.units}$

Explanation :

$area \: of \: square \: = side \times side$

$= (3m + 2n - 4l) \times (3m + 2n - 4l)$

$= (3m + 2n - 4l)^{2}$

$(a + b + c) ^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc + 2ca$

use this identidy to find the answer