Question

find the area of square whose side length is 3m+2n-4l​

Answer 1

Answer:(3m+2n-4)^2

Step-by-step explanation:

Answer 2

The area of the square with the given side is$9m^{2} +4n^{2} +16l^{2}+12mn-16nl-24ml.$

Here, according to the given information, we are given that,

The side of a square is given as,

$3m+2n-4l$.

Now, in order to find the area of a square, we know that the area of a square is the square of the length of one of its sides. Squaring the length of the side of a square will give us the area of this square.

Now, the area of the square with the given side that is $3m+2n-4l$ is,

$(3m+2n-4l)^{2}$

Now, we know that the well-known algebraic identity is, $(a+b+c)^{2} =a^{2} +b^{2} +c^{2} +2(ab+bc+ca)$.

Now, implementing this algebraic identity in finding the area of the above square, we get,

$(3m+2n-4l)^{2} \\=9m^{2} +4n^{2} +16l^{2} +2(6mn-8nl-12ml)\\=9m^{2} +4n^{2} +16l^{2}+12mn-16nl-24ml.$

Hence, the area of the square with the given side is $9m^{2} +4n^{2} +16l^{2}+12mn-16nl-24ml.$

Learn more here

https://brainly.in/question/892370

#SPJ3