Question

Find the area of that sector of a circle of radius 3·5 cm
whose central angle is 90 .

Answer 1

Answer:

Radius- 3.5 cm

Angle - 90°

Area of sector:

$= \frac{theta}{360} \times \pi {r}^{2}$

$= \frac{90}{360} \times \frac{22}{7} \times 3.5 \times 3.5$

$= \frac{11 \times 35}{2 \times 2 \times 10}$

$= \frac{385}{40}$

$= 9.625$ cm²

Hope it helps you!