find the area of the 15 cm 5. In the adjoining figure, ABC is a right angled triangle at A and AD is perpendicular to BC. If BC = 17 cm and AC = 15 cm, find: 17 cm (i) the area of AABC. (ii) the length of altitude AD. ter is 20 cm .
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Step-by-step explanation:
Using Pythagoras theorem in △ABC
(AB)
2
+(BC)
2
=(AC)
2
(15)
2
+(8)
2
=(AC)
2
⇒(AC)
2
=225+64=289
⇒AC=17cm
Now inradius r=
s
Δ
where Δ is the area of triangle and s is semi perimeter.
Δ=
2
1
×8×15=60
s=
2
8+15+17
=
2
40
=20
⇒r=
s
Δ
=
20
60
=3cm
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