Question

Find the area of the below given polygon. pls no spams :( I want step by step​

Answer 1

★Solution:-

Area Of Trapezium (A) :-

$\green{A= \frac{A+ B}{2} \times h} \\ \\ \color{teal} \implies \: A= \frac{30 + 10}{2} \times 10 \\ \\ \color{green} \implies \: a = 200 {cm}^{2}$

Area Of Trapezium (B):-

$\color{green}B = \frac{A+ B}{2} \times h \\ \\ \color{green}A= B \\ \\ \color{lime}Area \: Of \: Rectangle = l \times B \\ \\ \color{teal}= 10 \times 50 \\ \\ \color{darkgreen}= 500 {cm}^{2}$

Area of Whole Figure

= Area of both Trapezium + Area of Rectangle

$\color {lime}= 500 + 200 + 200 \\ \\ \color{teal} = 900 {cm}^{2}$

Hence, The Area Of Figure is 900cm²

Answer 2

Step-by-step explanation:

Area Of Trapezium (A) :-

\begin{gathered} \green{A= \frac{A+ B}{2} \times h} \\ \\ \color{teal} \implies \: A= \frac{30 + 10}{2} \times 10 \\ \\ \color{green} \implies \: a = 200 {cm}^{2} \end{gathered}

A=

2

A+B

×h

⟹A=

2

30+10

×10

⟹a=200cm

2

Area Of Trapezium (B):-

\begin{gathered} \color{green}B = \frac{A+ B}{2} \times h \\ \\ \color{green}A= B \\ \\ \color{lime}Area \: Of \: Rectangle = l \times B \\ \\ \color{teal}= 10 \times 50 \\ \\ \color{darkgreen}= 500 {cm}^{2} \\ \\ \end{gathered}

B=

2

A+B

×h

A=B

AreaOfRectangle=l×B

=10×50

=500cm

2

Area of Whole Figure

= Area of both Trapezium + Area of Rectangle

\begin{gathered} \color {lime}= 500 + 200 + 200 \\ \\ \color{teal} = 900 {cm}^{2} \end{gathered}

=500+200+200

=900cm

2