Question

find the area of the board​

Answer 1

Answer:

24 unit square(hopefully I am right)

Step-by-step explanation:

Join AC

Area of board = Area of ∆ABC + Area of ∆ACD

Area of ∆ABC =

[2(2-6) + 8(6-2) + 8(2-2)]÷2= 12 unit square

Area of ∆ADC=

[2(6-6) + 2(6-2) + 8(2-6)]÷2= -12 unit square

But since area cannot be negative

Therefore, Area of ∆ADC = |-12| unit square = 12 unit square

=> Area of Board = 12 + 12 = 24 unit square

HOPE IT HELPS

Answer 2

Answer:

length AB= $\sqrt{(x_{2}-x_{1})^{2} +(y_{2} -y_{1})^{2} }$

        = $\sqrt{(8-2)^{2}+(2-2)^{2} }$

       =  $\sqrt{36+0}$

       =$\sqrt{36}$

        = 6 units

breadth BC =  $\sqrt{(x_{2}-x_{1})^{2} +(y_{2} -y_{1})^{2} }$

                    =$\sqrt{(8-8)^{2}+(2-6)^{2} }$

                    = $\sqrt{0+16}$

                    =4 units

area = lb

        =6 ×4

        24$units^{2}$

mark it as brainliest answer

mark it as brainliest answer

Step-by-step explanation: