Question

Find the area of the canvas required to make a conical tent 14 m high and 96 m in diameter .Given that:
i:20% of the canvas is used in folds and stitching's .

ii: canvas used in folds and stitching's is 20% of the curved surface area of the tent.

No spams need quality answer. By any maths aryabhatta !!

Answer 1

Answer:

Hey mate here is your answer:

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Solution:

→For the conical tent :

→Height, h=14 m and radius , r = $\frac{96}{2} \:m=48\:m$,

→l²-h²+r²⇒l²=14²+48²,

→                       l= 50 m,∴ slant height = 50 m,

→Curved surface area of the tent = $\pi rl$,

→           $\frac{22}{7}$×48×50 m² = $\frac{52800}{7}$ m².

I: let the area of the canvas required be x m²,

→x-20% of x = $\frac{52800}{7}$ m²,

→                     x=$\frac{66000}{7}$ m² = $9428\frac{4}{7}$ m²,

→∴ The area of the canvas = $9428\frac{4}{7}$ m².

II : Area of the canvas required = C.S.A of the tent + 20% of it

= $\frac{52800}{7}$ m² + 20 % of

→$\frac{63360}{7}$ m ² = $9051\frac{3}{7}$ m².

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$\huge\boxed\boxed{\text{Hope it helps you}}$$\huge\boxed{\text{Hope it helps you}}$

Answer 2

Step-by-step explanation:

Hiiiiiiiiiiii Shekhar:)

Tumhara wo wale Question ka answer isme de rhi hu :)

So I will choose

3,7,8,10

Btw sneha is using ur I'd presently

She told me......!!!!!

hahahaha.......