Find the area of the circle whose area is equal to sum of areas of the two circles of radius 10cm and 24cm
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radius of first circle = 10cm
area of the first circle =π r²
=3.14*10*10
=314cm²
radius of second circle = 24cm
area of second circle =π r²
=3.14*24*24
=1808.64cm²
sum of area of two circles = 314+1808.64
=2122.64cm²
∴area of the circle =2122.64
hope it will help you
∴
area of the first circle =π r²
=3.14*10*10
=314cm²
radius of second circle = 24cm
area of second circle =π r²
=3.14*24*24
=1808.64cm²
sum of area of two circles = 314+1808.64
=2122.64cm²
∴area of the circle =2122.64
hope it will help you
∴
rg396112:
Vvv thnx...
Answered by
0
Area of the circle =2122.64 cm²
Step-by-step explanation:
Given:
Radius of 1st circle = 10 cm
Radius of 2nd circle = 24 cm
Computation:
Area of 1st circle = π r²
=22/7×10×10
= 314 cm²
Area of 2nd circle = π r²
=22/7×24×24
= 1808.64 cm²
Area of new circle = Sum of area of two circles
= 314 cm² + 1808.64 cm²
= 2122.64 cm²
Area of the circle = 2122.64 cm²
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https://brainly.in/question/15006695
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