Question

Find the area of the circle (x+1)(x+2)+(y-1)(y+3)=0

Answer 1

Answer:

Area of circle = π. r^2 = π. 17/4= 22×17/4= 187/2= 93.5 units ^2.

Answer 2

$(x + 1)(x + 2) + (y - 1)(y + 3) = 0$

$or \: \: x^2+3x+2+y^2+2y-3=0</p><p></p><p></p><p>or. (x+3/2)^2+(y+1)^2=1+9/4+1= 17/4</p><p></p><p>$

$or. (x+3/2)^2 +(y+1)^2 = (√17/2)^2</p><p></p><p>$

$thus \: \: coordinators \: \: of \: \: center \: \: ( - 3\2 \: - 1)and \: \: radius \: \: of \: \: circle \: \: is \: \: \sqrt{17 \2} units$

$area \: \: of \: \: circle \: \: = \pi .r \times 2 = \pi.r \: 17\4 = 22 \times 17 \4 = 187\2 = 93.5 \: \: units \times 2$

NOBITA221✔