Question

find the area of the combined figure given, formed by joining a semicircle of diameter 6 cm with a triangle of base 6 cm and height 9 cm. ​

Answer 1

Step-by-step explanation:

area of semicircle = 1/2 π r^2

area of triangle = 1/2 b h

$= (\frac{1}{2} \times \frac{22}{7} \times {3}^{2} ) + ( \frac{1}{2} \times 6 \times 9) \\ = \frac{11}{7} \times 9 + 3 \times 9 \\ = \frac{99}{7} + 18 \\ = \frac{99 + 126}{7} \\ = \frac{225}{7} = 32.14$