Question

find the area of the Crossroads at the right angles to each other throw the centre of the field

Answer 1

area of roads= area of two roads- area of center common square.
A=2×75+62×2-2×2
=150+124-4
=270m^2

area of road is 270m^2

Answer 2

The area of the crossroad at the right angles to each other throw the center of the field is 270 square meters.

Given that,

In the picture we have a crossroad.

We have to find the area of the crossroad at the right angles to each other throw the center of the field.

We know that,

Area of the crossroad is area of the total rectangle - 4× area of the rectangles of the 4 beside crossroad.

Area of the total rectangle is 75×62 = 4650

Area of the small rectangle = 30×$\frac{73}{2}$ = 1095

Area of the crossroad = 4650 - 4×1095 = 4650-4380 = 270

Therefore, The area of the crossroad at the right angles to each other throw the center of the field is 270 square meters.

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