Question

Find the area of the ellipse ax^2 + 2hxy + by^2 = 1​

Answer 1

Answer:

Prove that the area of the ellipse

Ax2+2Bxy+Cy2+2Dx+2Ey+F=0,Ax2+2Bxy+Cy2+2Dx+2Ey+F=0,

where AC−B2>0AC−B2>0, is equal to

S=−πΔ(AC−B2)3/2,S=−πΔ(AC−B2)3/2,

where

Δ=∣∣∣∣ABDBCEDEF∣∣∣∣.Δ=|ABDBCEDEF|.

I could prove that area of ellipse x2a2+y2b2=1x2a2+y2b2=1 is πab

Step-by-step explanation:

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