Question

find the area of the ellipse x^2/4 +y^2/25 = 1​

Answer 1

$\frac{ {x}^{2} }{4} + \frac{ {y}^{2} }{25} = 1 \\ \\ = > \frac{ {x}^{2} }{ {(2)}^{2} } + \frac{ {y}^{2} }{ {(5)}^{2} } = 1$

Here, axis a = 2 and b = 5

Then, Area of ellipse :

$\pi.ab = \frac{22}{7} \times 2 \times 5 = 31.42$

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