Question

Find the area of the equilateral triangle whose one side is 7 cm.

Answer 1

hey!

_______________

$Area\: of \:equilateral \:triangle \\ \\ \frac{{(\sqrt{3})}}{{4}} × {side}^{2}\\ \\ All\: sides\: are\: equal \\ \\ side = 7 \: cm \\ \\ \frac{{(\sqrt{3})}}{{4}} × 7 × 7 \\ \\ 49\frac{{(\sqrt{3})}}{{4}} {cm}^{2}$

Answer 2

Answer:

21.217 $cm^{2}$

Step-by-step explanation:

Given:- Side of an equilateral triangle = 7 cm.

To Find:- Area of the equilateral triangle whose sides = 7 cm.

Solution:-

As we know, An Equilateral triangle is a type of triangle whose sides are equal and makes an angle of 60° at each vertex.

As we know, Area of an equilateral triangle = $\frac{\sqrt{3} }{4} a^{2}$, where a = each side of an equilateral triangle.

Here, a = 7 cm.

∴ Area = $\frac{\sqrt{3} }{4}$ × 7 × 7  $cm^{2}$

           = $\sqrt{3}$ × $\frac{49}{4}$ $cm^{2}$

           = 1.732 × 12.25 $cm^{2}$         [∴ $\sqrt{3}$ = 1.732 ]

           = 21.217 $cm^{2}$

Therefore, Area of the equilateral triangle whose one side is 7 cm = 21.217 $cm^{2}$

#SPJ3