Find the area of the face of the each of the following letter.The dimension are in centimeter, and all corner are at right angle
Answers
Step-by-step explanation:
soluction!!
\bold{area \: of \: rectangle = (l \times b)sq \: cm}areaofrectangle=(l×b)sqcm
\begin{gathered} \bold{area \: of \: l \:rectangle \: = 2 \frac{3}{4} \times 3 \ \frac{1}{2} } \\ < br / > \bold{ = \frac{11}{4} \times \frac{7}{2} = \frac{77}{8} } \\ \\ \bold{area \: of \: ll \: rectangle \: = 7 \ \frac{1}{2} \times 4 \ \frac{1}{4} } \\ \bold{ = \frac{15}{2} \times \frac{17}{4} = \frac{255}{8 } } \\ \\ \bold{area \: of \: lll \: rectangle \: = 4 \frac{1}{3} \times 3 } \\ \bold{ = \frac{9}{2} \times 3 = \frac{27}{2} } \\ \\ \bold{total \: area} \\ \bold{ = \frac{77}{8} + \frac{225}{8} + \frac{27}{2} } \\ \\ \bold{ = \frac{440}{8} } \\ \\ \bold{ = 55 {cm}^{2} }\end{gathered}
areaoflrectangle=2
4
3
×3
2
1
soluction!!
\bold{area \: of \: rectangle = (l \times b)sq \: cm}areaofrectangle=(l×b)sqcm
\begin{gathered} \bold{area \: of \: l \:rectangle \: = 2 \frac{3}{4} \times 3 \ \frac{1}{2} } \\ < br / > \bold{ = \frac{11}{4} \times \frac{7}{2} = \frac{77}{8} } \\ \\ \bold{area \: of \: ll \: rectangle \: = 7 \ \frac{1}{2} \times 4 \ \frac{1}{4} } \\ \bold{ = \frac{15}{2} \times \frac{17}{4} = \frac{255}{8 } } \\ \\ \bold{area \: of \: lll \: rectangle \: = 4 \frac{1}{3} \times 3 } \\ \bold{ = \frac{9}{2} \times 3 = \frac{27}{2} } \\ \\ \bold{total \: area} \\ \bold{ = \frac{77}{8} + \frac{225}{8} + \frac{27}{2} } \\ \\ \bold{ = \frac{440}{8} } \\ \\ \bold{ = 55 {cm}^{2} }\end{gathered}
areaoflrectangle=2
4
3
×3
2
1
<br/>=
4
11
×
2
7
=
8
77
areaofllrectangle=7
2
1
×4
4
1
=
2
15
×
4
17
=
8
255
areaoflllrectangle=4
3
1
×3
=
2
9
×3=
2
27
totalarea
=
8
77
+
8
225
+
2
27
=
8
440
=55cm
2
<br/>=
4
11
×
2
7
=
8
77
areaofllrectangle=7
2
1
×4
4
1
=
2
15
×
4
17
=
8
255
areaoflllrectangle=4
3
1
×3
=
2
9
×3=
2
27
totalarea
=
8
77
+
8
225
+
2
27
=
8
440
=55cm
2