Question

Find the area of the field ABCDEFG given alongside in which
41 – 30 m, AM = 70 m, AN = 90 m, AO = 110 m,
AE = 135 m, AB = 36 m, LG = 40 m, NF = 42 m,
MC = 54 m, and OD = 46 m.​

Answer 1

Answer:

where is the figure ???????

Answer 2

Area of ABCDEFG=9730 square m

Step-by-step explanation:

AL=30 m

AM=70 m, AN=90 m,AO=110 m

AE=135 m,AB=36 m

LG=40, NF=42 m,MC=54 and OD=46 m

LM=AM-AL=70-30=40 m

MN=AN-AM=90-70=20 m

LN=LM+MN=40+20=60 m

NO=AO-AN=110-90=20 m

OE=AE-AO=135-110=25 m

NE=NO+OE=20+25=45 m

OM=MN+NO=20+20=40 m

Area of triangle=$\frac{1}{2}\times base\times height$

Area of trapezium=$\frac{1}{2}\times (sum\;of\;parallel\;sides)\times height$

Area of ABCDEFG=Ar(ALG)+ar of trapezium(LNFG)+ar(FNE)+ar of trapezium(AMCB)+ar of trapezium(MCDO)+ar(OED)

Area of ABCDEFG=$\frac{1}{2}(30)(40)+\frac{1}{2}(40+42)(60)+\frac{1}{2}(42)(45)+\frac{1}{2}(36+54)(70)+\frac{1}{2}(54+46)(40)+\frac{1}{2}(25)(46)$

Area of ABCDEFG=$600+2460+945+3150+2000+575$ square m

Area of ABCDEFG=9730 square m

#Learns more:

https://brainly.in/question/15034012